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<front>
<journal-meta>
<journal-id journal-id-type="publisher-id">Front. Appl. Math. Stat.</journal-id>
<journal-title>Frontiers in Applied Mathematics and Statistics</journal-title>
<abbrev-journal-title abbrev-type="pubmed">Front. Appl. Math. Stat.</abbrev-journal-title>
<issn pub-type="epub">2297-4687</issn>
<publisher>
<publisher-name>Frontiers Media S.A.</publisher-name>
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<article-meta>
<article-id pub-id-type="doi">10.3389/fams.2025.1410533</article-id>
<article-categories>
<subj-group subj-group-type="heading">
<subject>Applied Mathematics and Statistics</subject>
<subj-group>
<subject>Original Research</subject>
</subj-group>
</subj-group>
</article-categories>
<title-group>
<article-title>Two-warehouse deterministic inventory model of expiry date known deteriorating items with just-in-time purchases for slotted backlogs</article-title>
</title-group>
<contrib-group>
<contrib contrib-type="author">
<name><surname>Thilagavathi</surname> <given-names>R.</given-names></name>
<xref ref-type="aff" rid="aff1"><sup>1</sup></xref>
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<contrib contrib-type="author" corresp="yes">
<name><surname>Viswanath</surname> <given-names>J.</given-names></name>
<xref ref-type="aff" rid="aff2"><sup>2</sup></xref>
<xref ref-type="corresp" rid="c001"><sup>&#x002A;</sup></xref>
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<name><surname>Mahdal</surname> <given-names>Miroslav</given-names></name>
<xref ref-type="aff" rid="aff3"><sup>3</sup></xref>
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<name><surname>Udaya Prakash</surname> <given-names>Jayavelu</given-names></name>
<xref ref-type="aff" rid="aff4"><sup>4</sup></xref>
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<contrib contrib-type="author" corresp="yes">
<name><surname>Salunkhe</surname> <given-names>Sachin</given-names></name>
<xref ref-type="aff" rid="aff5"><sup>5</sup></xref>
<xref ref-type="aff" rid="aff6"><sup>6</sup></xref>
<xref ref-type="corresp" rid="c001"><sup>&#x002A;</sup></xref>
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<aff id="aff1"><sup>1</sup><institution>Department of Mathematics, Rajalakshmi Engineering College</institution>, <addr-line>Chennai</addr-line>, <country>India</country></aff>
<aff id="aff2"><sup>2</sup><institution>Department of Mathematics, Vel Tech Rangarajan Dr. Sagunthala R&#x0026;D Institute of Science and Technology</institution>, <addr-line>Chennai</addr-line>, <country>India</country></aff>
<aff id="aff3"><sup>3</sup><institution>Department of Control Systems and Instrumentation, Faculty of Mechanical Engineering, VSB-Technical University of Ostrava</institution>, <addr-line>Ostrava</addr-line>, <country>Czechia</country></aff>
<aff id="aff4"><sup>4</sup><institution>Department of Mechanical Engineering, Vel Tech Rangarajan Dr. Sagunthala R&#x0026;D Institute of Science and Technology</institution>, <addr-line>Chennai</addr-line>, <country>India</country></aff>
<aff id="aff5"><sup>5</sup><institution>Department of Biosciences, Saveetha School of Engineering, Saveetha Institute of Medical and Technical Sciences</institution>, <addr-line>Chennai</addr-line>, <country>India</country></aff>
<aff id="aff6"><sup>6</sup><institution>Department of Mechanical Engineering, Faculty of Engineering, Gazi University</institution>, <addr-line>Ankara</addr-line>, <country>T&#x00FC;rkiye</country></aff>
<author-notes>
<fn fn-type="edited-by" id="fn0001">
<p>Edited by: Aceng Sambas, Sultan Zainal Abidin University, Malaysia</p>
</fn>
<fn fn-type="edited-by" id="fn0002">
<p>Reviewed by: Nataliya Protsakh, Lviv Polytechnic National University, Ukraine</p>
<p>Hui-Ling Yang, Hungkuang University, Taiwan</p>
</fn>
<corresp id="c001">&#x002A;Correspondence: Sachin Salunkhe, <email>sachinsalunkhe@gazi.edu.tr</email>; J. Viswanath, <email>jviswanath@veltech.edu.in</email></corresp>
</author-notes>
<pub-date pub-type="epub">
<day>05</day>
<month>02</month>
<year>2025</year>
</pub-date>
<pub-date pub-type="collection">
<year>2025</year>
</pub-date>
<volume>11</volume>
<elocation-id>1410533</elocation-id>
<history>
<date date-type="received">
<day>01</day>
<month>04</month>
<year>2024</year>
</date>
<date date-type="accepted">
<day>13</day>
<month>01</month>
<year>2025</year>
</date>
</history>
<permissions>
<copyright-statement>Copyright &#x00A9; 2025 Thilagavathi, Viswanath, Mahdal, Udaya Prakash and Salunkhe.</copyright-statement>
<copyright-year>2025</copyright-year>
<copyright-holder>Thilagavathi, Viswanath, Mahdal, Udaya Prakash and Salunkhe</copyright-holder>
<license xlink:href="http://creativecommons.org/licenses/by/4.0/">
<p>This is an open-access article distributed under the terms of the Creative Commons Attribution License (CC BY). The use, distribution or reproduction in other forums is permitted, provided the original author(s) and the copyright owner(s) are credited and that the original publication in this journal is cited, in accordance with accepted academic practice. No use, distribution or reproduction is permitted which does not comply with these terms.</p>
</license>
</permissions>
<abstract>
<sec id="sec80">
<title>Introduction</title>
<p>A two-warehouse deterministic inventory system for purchases of short-expiry items with low purchasing costs is modelled. The total cost of the replenishment cycle is arrived at by implementing multiple just-in-time (JIT) purchases for the slotted backlogged customers. It avoids the loss of impatient customers who are virtually waiting for a long time.</p>
</sec>
<sec id="sec81">
<title>Methods</title>
<p>The inventory system consists of an own warehouse (OW) with finite capacity and an integral rental warehouse (RW) with unlimited capacity. Handlingand selling items with short expiry is a challenging task in revenue generation in commercial inventory management. Two categories of identical items are purchased: Category 1 consists of items whose expiry date falls within the replenishment cycle period, while Category 2 includes items with longer expiry dates. Unlike the traditional assumption in the literature, the items in Category 1 are purchased for a low price and stored in RW. Items in Category 2 are stored in OW. Due to short expiry of items, demands are first satisfied from the RW. The items in the RW are emptied before the expiry date of the items, due to expiry date-dependent deterioration and constant demand. At the same time, the items in the OW are decreasing due to exponential demand and constant deterioration. All customers are backlogged during the stock-out period and slotted into three intervals. The finite number of JIT purchases is employed to satisfy the backlogged slotted demands that occur before the last slot.</p>
</sec>
<sec id="sec82">
<title>Results and Discussion</title>
<p>We optimize the total cost of the replenishment cycle, RW utility, and total items purchased. The model is illustrated with an appropriate numerical example, and extensive sensitivity analysis is conducted on the system&#x2019;s performance.</p>
</sec>
</abstract>
<kwd-group>
<kwd>warehouse</kwd>
<kwd>inventory</kwd>
<kwd>just-in-time purchases</kwd>
<kwd>backlog</kwd>
<kwd>expiry date</kwd>
</kwd-group>
<counts>
<fig-count count="7"/>
<table-count count="3"/>
<equation-count count="28"/>
<ref-count count="26"/>
<page-count count="10"/>
<word-count count="7510"/>
</counts>
<custom-meta-wrap>
<custom-meta>
<meta-name>section-at-acceptance</meta-name>
<meta-value>Dynamical Systems</meta-value>
</custom-meta>
</custom-meta-wrap>
</article-meta>
</front>
<body>
<sec sec-type="intro" id="sec1">
<label>1</label>
<title>Introduction</title>
<p>Just-in-time (JIT) purchasing is a strategic approach to establishing and managing the supply chain that effectively minimizes inventory, facilitates frequent purchases, ensures high quality, fosters strong supplier relationships, and improves production efficiency. This study is based on an unusual two-warehouse inventory model with a finite JIT purchase to satisfy the backlog slots. Supply chain management is the main portfolio of any industrial system. JIT production and JIT purchasing policies have revolutionized cost optimization in supply chain management for large-scale industries. The inventory model assists managers in controlling inventory levels by addressing the queries of how much, when, and what to buy to purchase in order to maintain sufficient quantities of inventory to meet customer demand. The supplier offers discounts on the purchase of items that either have a short expiration date or are purchased in bulk. Any commercial business faces business risks that lead to an inadequate amount of profit due to some uncertainties, including changes in environmental conditions, customer needs and preferences, item deterioration, and heavy and increasing competition in the market. Retailers often make risky decisions to maximize profits by purchasing items with short expiration dates, items on discount, and items at regular prices. It increases their income if all items are sold within the stipulated time limit. The literature study that contributed to initiating the current study is as follows:</p>
<p>The article (<xref ref-type="bibr" rid="ref1">1</xref>) links supply chain management, just-in-time delivery, and quality management and analyzes how these elements contribute to improved company performance. The results exhibit the organization&#x2019;s point of view on the links at both strategic and operational levels. In Ismail Salaheldin (<xref ref-type="bibr" rid="ref2">2</xref>), it is identified that JIT performance is strongly related to human resource modification initiatives. The findings indicate that, with careful consideration of each unique enterprise, the JIT concept can be effectively applied to Egyptian manufacturing enterprises. JIT is a strategic theory that encourages uniqueness and worth. It has practical consequences. In the work of Duclos et al. (<xref ref-type="bibr" rid="ref3">3</xref>), Toyota Motor Company was commended for creating and executing a strategy that boosted its competitiveness in the automobile industry. JIT is defined by the American Production and Inventory Control Society as a production excellence mindset focused on organized waste removal and continued output growth. It covers all phases of the production process, from raw material conversion to the level of distribution. The JIT purchasing method was investigated in Christensen (<xref ref-type="bibr" rid="ref4">4</xref>) as an aspect of the Freight Transport Association&#x2019;s response to the transportation argument and was found to reduce container movements due to improvements in technology and vehicle utilization. It also allows the company to show advancements, environmental advantages, and customer relations and suggests additional savings.</p>
<p>The supplier&#x2013;manufacturer ties in the JIT setting and their influence on the effectiveness of JIT execution is discussed in Wafa et al. (<xref ref-type="bibr" rid="ref5">5</xref>). Additionally, it investigates the functions of data, collaboration, vendor relationships, and supplier closeness in JIT performance. A metric for assessing JIT effectiveness is proposed, incorporating both monetary and non-monetary factors. The existence of complementarity among the internal and external <inline-formula>
<mml:math id="M1">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula> bundles is tested in Furlan et al. (<xref ref-type="bibr" rid="ref6">6</xref>). It is shown that the upstream and downstream of JIT are complemented by analyzing the international research project data set in optimizing operational performances. In Hwang and Hahn (<xref ref-type="bibr" rid="ref7">7</xref>), it examines the best strategy for purchasing items with the assumption that the demand rate is a function of the present stock level and that each unit has an expiry date. The susceptibility of decision factors while changing the parameter values is investigated using a mathematical model and solution technique. An inventory model with price, freshness, and stock-dependent demand is proposed in Feng et al. (<xref ref-type="bibr" rid="ref8">8</xref>). They determine unit price, total cycle time, and ending-inventory level, which maximize the total profit. The study (<xref ref-type="bibr" rid="ref9">9</xref>) examines a more realistic scenario in which a product&#x2019;s deterioration rate steadily rises as the expiration date approaches. The factors of choice that minimize the overall cost are the optimum cycle duration and the cycle fraction of no shortages. The model is validated by a numerical example.</p>
<p>The retailers&#x2019; and suppliers&#x2019; purchasing policies are established in Hsu et al. (<xref ref-type="bibr" rid="ref10">10</xref>) with the constraints of product deterioration, expiry date, lead time, capital limits, and seasonal demand. Total order quantity, stock-out period, optimum replenishment cycle, and source handling cost for the supplier are estimated. In Wu et al. (<xref ref-type="bibr" rid="ref11">11</xref>), an EOQ model for retailers is suggested to determine the optimum credit period and cycle time for the supplier-retailer&#x2013;buyer supply chain. It explains how to increase sales and income while increasing trade credit. This article (<xref ref-type="bibr" rid="ref12">12</xref>) shows that the optimum restocking cycle time for a store is not just something that happens; it is also unique, making it easier to identify a solution. The DCF analysis is used to calculate all pertinent costs. Both numerical examples and risk analysis are used to explain the different issues and gain management insights. The optimum lot-sizing strategies for retailers who sell deteriorating goods to trade payables while providing partial trade credit to reduce risk are suggested in Wu et al. (<xref ref-type="bibr" rid="ref13">13</xref>). The pseudo-convex fractional functions are used to attain the best answer and to get better discrimination terms. A deterministic replenishment system involving multiple warehouses with restricted storage space and a time-dependent demand rate is discussed in Zhou (<xref ref-type="bibr" rid="ref14">14</xref>). The products from the rented warehouse are moved to the owned warehouse in a continuous release pattern.</p>
<p>A two-storage inventory system was developed for deteriorating goods with advanced payment, a constant partial backlog, and selling price-dependent demand (<xref ref-type="bibr" rid="ref15">15</xref>). Product promotion is an essential component of inventory research, as both price and availability play a vital role in attracting customers. The study (<xref ref-type="bibr" rid="ref16">16</xref>) considered these aspects along with deteriorating items of price- and stock-dependent demand in partially backlogged storage. A two-storage inventory approach with an advance payment option has been developed in Khan et al. (<xref ref-type="bibr" rid="ref17">17</xref>) for three different scenarios based on varying beginning times for degradation in both warehouses. Three optimal issues have been identified, and their optimality is mathematically demonstrated. An algorithm is suggested to solve the model. This article (<xref ref-type="bibr" rid="ref18">18</xref>) includes an EOQ inventory model based on the price and stock-dependent demand with the shortfalls in backlog. The inventory issue is transformed into a non-linear constraint optimum issue, and the cycle duration and overall cost are calculated using the Taylor series.</p>
<p>The study by Mashud et al. (<xref ref-type="bibr" rid="ref19">19</xref>) explores product deterioration in a production-inventory newsboy model using just-in-time deliveries. The classical optimization techniques of the distribution-free approach are employed with the consideration of a return and post-sale warranty policy to improve business and attract customers. Validity is demonstrated through theoretical development and numerical examples. The article by Mashud et al. (<xref ref-type="bibr" rid="ref20">20</xref>) presents a two-warehouse sustainable inventory model by considering the factors of price-dependent demand, non-instantaneous deterioration rate, discount facility, partial backlog, and various payment options for both retailers and suppliers. The classical optimization technique is employed to maximize the total profit of the system. In Mashud et al. (<xref ref-type="bibr" rid="ref21">21</xref>), the study on the inventory model explores optimal pricing and inventory strategies for deteriorating products with price-dependent demand and advanced payment systems, incorporating time-dependent holding costs. It highlights how advanced payment periods, installment numbers, product lifecycle, purchasing cost, and demand function significantly impact total profit. A solution to the problem involves placing two orders one period apart, with the second order designed to fulfill any demand unmet by the first order (<xref ref-type="bibr" rid="ref22">22</xref>). It facilitates the reduction of shortages and minimizes the total costs.</p>
<p>The study (<xref ref-type="bibr" rid="ref23">23</xref>) facilitates anyone to know the impact of monetary inflation on a two-warehouse inventory system by emphasizing stock-dependent demand and flexible payment options in attaining optimum total cost. The article (<xref ref-type="bibr" rid="ref24">24</xref>) projects a two-warehouse inventory model with ramp-type demand and constant deterioration, utilizing a rental warehouse for surplus goods and prepayment in equal installments. Stock-outs are addressed through emergency purchases, and the model&#x2019;s effectiveness is demonstrated through numerical examples. The article (<xref ref-type="bibr" rid="ref25">25</xref>) investigates two-warehouse inventory systems integrated with a production unit, aiming to optimize the total production cycle and cost. It employs an analytical optimization approach using the discriminant method, focusing on unit utility, fluctuating deterioration rates, and varying demand and production parameters. The sensitivity of unit utility, fluctuating deterioration rates, variable demand, and production parameters are revealed by numerical values. The article (<xref ref-type="bibr" rid="ref26">26</xref>) analyses a single product inventory with two warehouses, varying storage costs to maintain quality and prevent deterioration, and unpredictable demand patterns. It proposes an instantaneous replenishment policy and assumes payment delays, demonstrating the optimal overall cost.</p>
<p>In today&#x2019;s unpredictable market conditions and due to rapidly changing customer demands, any business faces a stock-out state in the course of the entire replenishment cycle. Customers&#x2019; behaviors are presently more unpredictable and less dependable, which results in a small percentage of customers only willing to wait for the product until it gets replenished in the inventory during the stock-out period. The complementary percentage of the customer is treated as lost customers. It is a great challenge to retailers, and they are forced to go for a finite number of JIT purchases by slotting the stock-out time interval. Since the JIT purchase policy is not always profitable in scenarios of inventory management, the cost price of the product also increases continuously. Moreover, retailers are offered a variety of discount offers upon bulk ordering.</p>
<p>The article flow is depicted in <xref ref-type="fig" rid="fig1">Figure 1</xref>.</p>
<fig position="float" id="fig1">
<label>Figure 1</label>
<caption>
<p>Diagram for the article flow.</p>
</caption>
<graphic xlink:href="fams-11-1410533-g001.tif"/>
</fig>
</sec>
<sec id="sec2">
<label>2</label>
<title>Notations and assumptions</title>
<sec id="sec3">
<label>2.1</label>
<title>Notations</title>
<p>This model is developed with the following notations:<table-wrap position="anchor" id="tab1">
<table frame="hsides" rules="groups">
<tbody>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M2">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>,</mml:mo>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">On-hand inventory levels at <inline-formula>
<mml:math id="M3">
<mml:msup>
<mml:mrow><mml:mphantom><mml:mn>1</mml:mn></mml:mphantom></mml:mrow><mml:mo>&#x2018;</mml:mo>
</mml:msup>
<mml:msup>
<mml:mi>t</mml:mi>
<mml:mo>&#x2019;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula> in<inline-formula>
<mml:math id="M4">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> and <inline-formula>
<mml:math id="M5">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
<mml:mtext>,</mml:mtext>
</mml:math>
</inline-formula> respectively.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M6">
<mml:mi>D</mml:mi>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Constant rate of demand for the items in<inline-formula>
<mml:math id="M7">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M8">
<mml:mi>A</mml:mi>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:msup>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Exponential demand rate for the items in<inline-formula>
<mml:math id="M9">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>, where <inline-formula>
<mml:math id="M10">
<mml:mi>A</mml:mi>
<mml:mo>,</mml:mo>
<mml:mi>&#x03BB;</mml:mi>
<mml:mo>&#x003E;</mml:mo>
<mml:mn>0.</mml:mn>
</mml:math>
</inline-formula></td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M11">
<mml:mi>L</mml:mi>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Expiry time point for the items in<inline-formula>
<mml:math id="M12">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M13">
<mml:mi>&#x03D5;</mml:mi>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Expiry date-dependent deterioration rate of the items in <inline-formula>
<mml:math id="M14">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>, where <inline-formula>
<mml:math id="M15">
<mml:mn>0</mml:mn>
<mml:mo>&#x2264;</mml:mo>
<mml:mi>&#x03D5;</mml:mi>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mfrac>
<mml:mn>1</mml:mn>
<mml:mrow>
<mml:mn>1</mml:mn>
<mml:mo>+</mml:mo>
<mml:mi>L</mml:mi>
<mml:mo>&#x2212;</mml:mo>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:mfrac>
<mml:mo>&#x2264;</mml:mo>
<mml:mn>1</mml:mn>
</mml:math>
</inline-formula>.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M16">
<mml:mi>&#x03B8;</mml:mi>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Constant deterioration rate of the items in<inline-formula>
<mml:math id="M17">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M18">
<mml:mi mathvariant="script">F</mml:mi>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Total number of items purchased per replenishment cycle.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M19">
<mml:mi mathvariant="script">R</mml:mi>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Total number of expiry date-constrained items that are purchased.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M20">
<mml:msub>
<mml:mi>W</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Maximum<inline-formula>
<mml:math id="M21">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>capacity.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M22">
<mml:msub>
<mml:mi>W</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Expiry date-constrained items which are stored in <inline-formula>
<mml:math id="M23">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M24">
<mml:msub>
<mml:mi mathvariant="script">B</mml:mi>
<mml:mi>i</mml:mi>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Number of <inline-formula>
<mml:math id="M25">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula> purchasing quantity to satisfy the slot-<inline-formula>
<mml:math id="M26">
<mml:mi>i</mml:mi>
</mml:math>
</inline-formula> backlog customers, <italic>i</italic>&#x202F;=&#x202F;1, 2.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M27">
<mml:msub>
<mml:mi mathvariant="script">B</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Number of backlogs in slot-3 is satisfied from ordered <inline-formula>
<mml:math id="M28">
<mml:mi mathvariant="script">R</mml:mi>
</mml:math>
</inline-formula>items.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M29">
<mml:mi>I</mml:mi>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Ordering cost for the regular order.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M30">
<mml:msub>
<mml:mi>J</mml:mi>
<mml:mi>i</mml:mi>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Ordering cost of the<inline-formula>
<mml:math id="M31">
<mml:msup>
<mml:mi>i</mml:mi>
<mml:mrow>
<mml:mi>t</mml:mi>
<mml:mi>h</mml:mi>
</mml:mrow>
</mml:msup>
<mml:mspace width="0.25em"/>
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula>purchase order, where <inline-formula>
<mml:math id="M32">
<mml:mi>i</mml:mi>
<mml:mo>=</mml:mo>
<mml:mn>1</mml:mn>
<mml:mo>,</mml:mo>
<mml:mn>2</mml:mn>
</mml:math>
</inline-formula>.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M33">
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Purchasing cost of an expiry date unconstrained item.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M34">
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Purchasing cost of an expiry date-constrained item.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M35">
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mi>i</mml:mi>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Purchasing cost of the <inline-formula>
<mml:math id="M36">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula> purchase item for a customer in the slot <inline-formula>
<mml:math id="M37">
<mml:mi>i</mml:mi>
</mml:math>
</inline-formula>, where <inline-formula>
<mml:math id="M38">
<mml:mi>i</mml:mi>
<mml:mo>=</mml:mo>
<mml:mn>3</mml:mn>
<mml:mo>,</mml:mo>
<mml:mn>4</mml:mn>
</mml:math>
</inline-formula>.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M39">
<mml:msub>
<mml:mi>h</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mo>,</mml:mo>
<mml:msub>
<mml:mi>h</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Holding cost of tan item in <inline-formula>
<mml:math id="M40">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> and <inline-formula>
<mml:math id="M41">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> respectively.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M42">
<mml:msub>
<mml:mi>d</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mo>,</mml:mo>
<mml:msub>
<mml:mi>d</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Deterioration cost of an item in <inline-formula>
<mml:math id="M43">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> and <inline-formula>
<mml:math id="M44">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
<mml:mtext>,</mml:mtext>
</mml:math>
</inline-formula> respectively.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M45">
<mml:mi>b</mml:mi>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Cost for backlogging a customer.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M46">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Non-instantaneous deterioration length of <inline-formula>
<mml:math id="M47">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M48">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Time interval in which the <inline-formula>
<mml:math id="M49">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> becomes empty.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M50">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Time interval in which the <inline-formula>
<mml:math id="M51">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> becomes empty.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M52">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">The time point in which the first <inline-formula>
<mml:math id="M53">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula> purchase was made.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M54">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">The time point in which the second <inline-formula>
<mml:math id="M55">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula> purchase was made.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M56">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Total replenishment cycle length.</td>
</tr>
<tr>
<td align="left" valign="top"><inline-formula>
<mml:math id="M57">
<mml:msubsup>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula>, <inline-formula>
<mml:math id="M58">
<mml:msubsup>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula></td>
<td align="left" valign="top">Optimal values of <inline-formula>
<mml:math id="M59">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mo>,</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>.</td>
</tr>
<tr>
<td align="left" valign="top">
<inline-formula>
<mml:math id="M60">
<mml:mi>T</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>
</td>
<td align="left" valign="top">Optimal value of the total cost <inline-formula>
<mml:math id="M61">
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mtext>.</mml:mtext>
</mml:math>
</inline-formula></td>
</tr>
</tbody>
</table>
</table-wrap></p>
</sec>
<sec id="sec4">
<label>2.2</label>
<title>Assumptions</title>
<p>The optimization study of the model proceeded with the following assumptions:</p>
<list list-type="bullet">
<list-item>
<p>The rate of replenishment is infinite, and replenishment happens instantly.</p>
</list-item>
<list-item>
<p>The lead time is negligible.</p>
</list-item>
<list-item>
<p>The planning horizon is limited.</p>
</list-item>
<list-item>
<p>All items are subject to deterioration, and items should never be sold just after their&#x2019; expiry date <inline-formula>
<mml:math id="M62">
<mml:mi>L</mml:mi>
</mml:math>
</inline-formula> not even for a lower cost.</p>
</list-item>
<list-item>
<p>A finite number of JIT ordering strategies is implemented.</p>
</list-item>
<list-item>
<p>Items with unconstrained expiry date (That means the items whose expiry date falls after the time point <inline-formula>
<mml:math id="M63">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>) are stored in<inline-formula>
<mml:math id="M64">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>.</p>
</list-item>
<list-item>
<p>Items with constrained expiry date (That means, the items whose expiry date ends at <inline-formula>
<mml:math id="M65">
<mml:mi>L</mml:mi>
</mml:math>
</inline-formula> which lies within the time point <inline-formula>
<mml:math id="M66">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>) are stored in<inline-formula>
<mml:math id="M67">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>.</p>
</list-item>
<list-item>
<p>The space of <inline-formula>
<mml:math id="M68">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> is limited, but<inline-formula>
<mml:math id="M69">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>is of infinite capacity.</p>
</list-item>
<list-item>
<p>The deterioration cost of an item in <inline-formula>
<mml:math id="M70">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> is smaller than the deterioration cost of an item in <inline-formula>
<mml:math id="M71">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>.</p>
</list-item>
<list-item>
<p>The first and second <inline-formula>
<mml:math id="M72">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula> purchases satisfy the backlog customers of slot-1 and slot-2, respectively.</p>
</list-item>
<list-item>
<p>The slot-3 backlog customers are satisfied by the purchase of constrained expiry date items at the start of the next replenishment cycle.</p>
</list-item>
</list>
<disp-formula id="E1">
<mml:math id="M73">
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mo>&#x003C;</mml:mo>
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:mo>&#x003C;</mml:mo>
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
<mml:mo>&#x003C;</mml:mo>
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
<mml:mtext>.</mml:mtext>
</mml:math>
</disp-formula>
<list list-type="bullet">
<list-item>
<p>Items in<inline-formula>
<mml:math id="M74">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>are of a non-instantaneous deteriorated nature.</p>
</list-item>
</list>
</sec>
</sec>
<sec id="sec5">
<label>3</label>
<title>Model formulation and solution</title>
<p>The retailer purchases <inline-formula>
<mml:math id="M75">
<mml:mi mathvariant="script">F</mml:mi>
</mml:math>
</inline-formula> (includes the fraction of constrained expiry date items) items at first. It is stored <inline-formula>
<mml:math id="M76">
<mml:msub>
<mml:mi>W</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
</mml:math>
</inline-formula> number of unconstrained expiry date items in<inline-formula>
<mml:math id="M77">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> as it is its maximum capacity. The remaining<inline-formula>
<mml:math id="M78">
<mml:msub>
<mml:mi>W</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mi mathvariant="script">F</mml:mi>
<mml:mo>&#x2212;</mml:mo>
<mml:msub>
<mml:mi mathvariant="script">B</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
<mml:mo>&#x2212;</mml:mo>
<mml:msub>
<mml:mi>W</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
</mml:math>
</inline-formula> items are stored in <inline-formula>
<mml:math id="M79">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> after satisfying the <inline-formula>
<mml:math id="M80">
<mml:msub>
<mml:mi mathvariant="script">B</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:math>
</inline-formula> backlogs of slot-3 of the previous cycle. The items in <inline-formula>
<mml:math id="M81">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> reach zero at <inline-formula>
<mml:math id="M82">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:math>
</inline-formula> due to the joint effect of demand and deterioration. Once <inline-formula>
<mml:math id="M83">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> is empty, further demands are satisfied by the items from <inline-formula>
<mml:math id="M84">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>. Items in <inline-formula>
<mml:math id="M85">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> are subject to non-instantaneous deteriorated nature, which prolongs time <inline-formula>
<mml:math id="M86">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>. After the time point <inline-formula>
<mml:math id="M87">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>, the items in <inline-formula>
<mml:math id="M88">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> start to decline because of the demand and deterioration; finally, it reaches zero at <inline-formula>
<mml:math id="M89">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>. The demands in the stock-out period are partitioned into three slots, say slot-<italic>i</italic>, <inline-formula>
<mml:math id="M90">
<mml:mi>i</mml:mi>
<mml:mo>=</mml:mo>
<mml:mn>1</mml:mn>
<mml:mo>,</mml:mo>
<mml:mn>2</mml:mn>
<mml:mo>,</mml:mo>
<mml:mn>3</mml:mn>
</mml:math>
</inline-formula>. First <inline-formula>
<mml:math id="M91">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula> purchase is made at the time point <inline-formula>
<mml:math id="M92">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
</mml:math>
</inline-formula> to satisfy the backlogged customers in slot-1, and second <inline-formula>
<mml:math id="M93">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula> purchase is made at <inline-formula>
<mml:math id="M94">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:math>
</inline-formula> to satisfy the backlogged customers in slot 2. Such an implementation of <inline-formula>
<mml:math id="M95">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula> purchase helps to avoid and reduce the backlog customers&#x2019; waiting time in the system. Backlogs in the interval <inline-formula>
<mml:math id="M96">
<mml:mfenced close="]" open="[" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:math>
</inline-formula> are satisfied by the constrained expiry date items at the beginning of the next replenishment cycle (see <xref ref-type="fig" rid="fig2">Figure 2</xref>).</p>
<fig position="float" id="fig2">
<label>Figure 2</label>
<caption>
<p>Flow of the inventory system per cycle.</p>
</caption>
<graphic xlink:href="fams-11-1410533-g002.tif"/>
</fig>
<p>The occurrence of dynamic change of items in the <inline-formula>
<mml:math id="M97">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> is subject to the expiry date-dependent deterioration and constant demand. It is represented by the following differential equation, which depicts that the rate of change of the inventory level in the <inline-formula>
<mml:math id="M98">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> is equal to the decrease in the inventory level <inline-formula>
<mml:math id="M99">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
</mml:math>
</inline-formula>due to deterioration among the items and the occurrence of demand. The inventory level <inline-formula>
<mml:math id="M100">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
</mml:math>
</inline-formula> at any time point<inline-formula>
<mml:math id="M101">
<mml:mi>t</mml:mi>
<mml:mo>&#x2208;</mml:mo>
<mml:mfenced close="]" open="[" separators=",">
<mml:mn>0</mml:mn>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:math>
</inline-formula> in <inline-formula>
<mml:math id="M102">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>is governed by the following equation:</p>
<disp-formula id="EQ7">
<label>(1)</label>
<mml:math id="M103">
<mml:mfrac>
<mml:mi>d</mml:mi>
<mml:mrow>
<mml:mi>d</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:mfrac>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>+</mml:mo>
<mml:mfrac>
<mml:mn>1</mml:mn>
<mml:mrow>
<mml:mn>1</mml:mn>
<mml:mo>+</mml:mo>
<mml:mi>L</mml:mi>
<mml:mo>&#x2212;</mml:mo>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:mfrac>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mo>&#x2212;</mml:mo>
<mml:mi>D</mml:mi>
</mml:math>
</disp-formula>
<p>Solving <xref ref-type="disp-formula" rid="EQ7">Equation 1</xref>, with the boundary condition <inline-formula>
<mml:math id="M104">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mn>0</mml:mn>
</mml:math>
</inline-formula>, we get <xref ref-type="disp-formula" rid="EQ8">Equation 2</xref></p>
<disp-formula id="EQ8">
<label>(2)</label>
<mml:math id="M105">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mi>D</mml:mi>
<mml:mfenced open="(" close=")">
<mml:mrow>
<mml:mn>1</mml:mn>
<mml:mo>+</mml:mo>
<mml:mi>L</mml:mi>
<mml:mo>&#x2212;</mml:mo>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:mfenced>
<mml:mo>ln</mml:mo>
<mml:mfenced open="(" close=")">
<mml:mfrac>
<mml:mrow>
<mml:mn>1</mml:mn>
<mml:mo>+</mml:mo>
<mml:mi>L</mml:mi>
<mml:mo>&#x2212;</mml:mo>
<mml:mi>t</mml:mi>
</mml:mrow>
<mml:mrow>
<mml:mn>1</mml:mn>
<mml:mo>+</mml:mo>
<mml:mi>L</mml:mi>
<mml:mo>&#x2212;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfrac>
</mml:mfenced>
<mml:mtext>,</mml:mtext>
<mml:mi>t</mml:mi>
<mml:mo>&#x2208;</mml:mo>
<mml:mfenced close="]" open="[" separators=",">
<mml:mn>0</mml:mn>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:math>
</disp-formula>
<p>At the same time, there is no demand for the items in <inline-formula>
<mml:math id="M107">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> up to the time point<inline-formula>
<mml:math id="M108">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>. However, item deterioration starts after the time point<inline-formula>
<mml:math id="M109">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
</mml:math>
</inline-formula> as the effect of non-instantaneous deterioration. The following differential equation represents the inventory level at<inline-formula>
<mml:math id="M110">
<mml:mi>t</mml:mi>
<mml:mo>&#x2208;</mml:mo>
<mml:mfenced close="]" open="[" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:math>
</inline-formula>.</p>
<disp-formula id="EQ9">
<label>(3)</label>
<mml:math id="M111">
<mml:mfrac>
<mml:mi>d</mml:mi>
<mml:mrow>
<mml:mi>d</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:mfrac>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>+</mml:mo>
<mml:mi>&#x03B8;</mml:mi>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mn>0</mml:mn>
</mml:math>
</disp-formula>
<p>Solving <xref ref-type="disp-formula" rid="EQ9">Equation 3</xref> with the boundary condition, <inline-formula>
<mml:math id="M112">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:msub>
<mml:mi>W</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
</mml:math>
</inline-formula>, we get <xref ref-type="disp-formula" rid="EQ10">Equation 4</xref></p>
<disp-formula id="EQ10">
<label>(4)</label>
<mml:math id="M113">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:msub>
<mml:mi>W</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03B8;</mml:mi>
<mml:mfenced open="(" close=")">
<mml:mrow>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:mo>&#x2212;</mml:mo>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:mfenced>
</mml:mrow>
</mml:msup>
<mml:mtext>,</mml:mtext>
<mml:mi>t</mml:mi>
<mml:mo>&#x2208;</mml:mo>
<mml:mfenced close="]" open="[" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:math>
</disp-formula>
<p>After <inline-formula>
<mml:math id="M115">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>, the demands are satisfied by the items stored in the <inline-formula>
<mml:math id="M116">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> because the <inline-formula>
<mml:math id="M117">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> becomes empty at <inline-formula>
<mml:math id="M118">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>0</mml:mn>
</mml:math>
</inline-formula>. So, the inventory level at the <inline-formula>
<mml:math id="M119">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> decreases due to both exponential demand rate and constant deterioration, and the inventory level at <inline-formula>
<mml:math id="M120">
<mml:mi>t</mml:mi>
<mml:mo>&#x2208;</mml:mo>
<mml:mfenced close="]" open="[" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:math>
</inline-formula>is expressed by the following differential equations,</p>
<disp-formula id="EQ11">
<label>(5)</label>
<mml:math id="M121">
<mml:mfrac>
<mml:mi>d</mml:mi>
<mml:mrow>
<mml:mi>d</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:mfrac>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>+</mml:mo>
<mml:mi>&#x03B8;</mml:mi>
<mml:mspace width="0.25em"/>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mo>&#x2212;</mml:mo>
<mml:mi>A</mml:mi>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:msup>
</mml:math>
</disp-formula>
<p>Solving <xref ref-type="disp-formula" rid="EQ11">Equation 5</xref> by applying the boundary condition,<inline-formula>
<mml:math id="M122">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mn>0</mml:mn>
</mml:math>
</inline-formula>, we get <xref ref-type="disp-formula" rid="EQ12">Equation 6</xref>.</p>
<disp-formula id="EQ12">
<label>(6)</label>
<mml:math id="M123">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mfrac>
<mml:mi>A</mml:mi>
<mml:mrow>
<mml:mi>&#x03B8;</mml:mi>
<mml:mo>+</mml:mo>
<mml:mi>&#x03BB;</mml:mi>
</mml:mrow>
</mml:mfrac>
<mml:mfenced open="[" close="]">
<mml:mrow>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mfenced open="(" close=")">
<mml:mrow>
<mml:mi>&#x03B8;</mml:mi>
<mml:mo>+</mml:mo>
<mml:mi>&#x03BB;</mml:mi>
</mml:mrow>
</mml:mfenced>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
<mml:mo>&#x2212;</mml:mo>
<mml:mspace width="0.25em"/>
<mml:mi>&#x03B8;</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:msup>
<mml:mo>&#x2212;</mml:mo>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:msup>
</mml:mrow>
</mml:mfenced>
<mml:mtext>,</mml:mtext>
<mml:mi>t</mml:mi>
<mml:mo>&#x2208;</mml:mo>
<mml:mfenced close="]" open="[" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:math>
</disp-formula>
<p>After the time point <inline-formula>
<mml:math id="M125">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:math>
</inline-formula>, the demands are fully backlogged and considered as three slots, such as the backlogs in the intervals <inline-formula>
<mml:math id="M126">
<mml:mfenced close="]" open="[" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mo>,</mml:mo>
<mml:mfenced close="]" open="[" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:math>
</inline-formula>, and<inline-formula>
<mml:math id="M127">
<mml:mfenced close="]" open="[" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:math>
</inline-formula>. The number of demands in the stock-out period is of exponential demand. The following differential equation represents the number of backlogs in the stock-out period, irrespective of the slots.</p>
<disp-formula id="EQ13">
<label>(7)</label>
<mml:math id="M128">
<mml:mfrac>
<mml:mi>d</mml:mi>
<mml:mrow>
<mml:mi>d</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:mfrac>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mi>A</mml:mi>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:msup>
</mml:math>
</disp-formula>
<p>The <xref ref-type="disp-formula" rid="EQ13">Equation 7</xref> may be solved by using the conditions<inline-formula>
<mml:math id="M129">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mn>0</mml:mn>
</mml:math>
</inline-formula>, <inline-formula>
<mml:math id="M130">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mn>0</mml:mn>
</mml:math>
</inline-formula>, and</p>
<p><inline-formula>
<mml:math id="M131">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mn>0</mml:mn>
</mml:math>
</inline-formula>, we get <xref ref-type="disp-formula" rid="EQ15">Equation 8</xref></p>
<disp-formula id="EQ15">
<label>(8)</label>
<mml:math id="M132">
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mfenced close="" open="{">
<mml:mtable equalrows="true" equalcolumns="true">
<mml:mtr>
<mml:mtd>
<mml:mfrac>
<mml:mi>A</mml:mi>
<mml:mi>&#x03BB;</mml:mi>
</mml:mfrac>
<mml:mfenced close="]" open="[">
<mml:mrow>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:msup>
<mml:mo>&#x2212;</mml:mo>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
</mml:mrow>
</mml:mfenced>
<mml:mo>,</mml:mo>
<mml:mi>t</mml:mi>
<mml:mo>&#x2208;</mml:mo>
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<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mtd>
</mml:mtr>
<mml:mtr>
<mml:mtd>
<mml:mfrac>
<mml:mi>A</mml:mi>
<mml:mi>&#x03BB;</mml:mi>
</mml:mfrac>
<mml:mfenced close="]" open="[">
<mml:mrow>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:msup>
<mml:mo>&#x2212;</mml:mo>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
</mml:mrow>
</mml:mfenced>
<mml:mo>,</mml:mo>
<mml:mi>t</mml:mi>
<mml:mo>&#x2208;</mml:mo>
<mml:mfenced close="]" open="[" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mtd>
</mml:mtr>
<mml:mtr>
<mml:mtd>
<mml:mfrac>
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<mml:mi>&#x03BB;</mml:mi>
</mml:mfrac>
<mml:mfenced close="]" open="[">
<mml:mrow>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:msup>
<mml:mo>&#x2212;</mml:mo>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
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<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
</mml:mrow>
</mml:mfenced>
<mml:mo>,</mml:mo>
<mml:mi>t</mml:mi>
<mml:mo>&#x2208;</mml:mo>
<mml:mfenced close="]" open="[" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mtd>
</mml:mtr>
</mml:mtable>
</mml:mfenced>
</mml:math>
</disp-formula>
<p>The total number of backlogged occurred in the three slots are represented in <xref ref-type="disp-formula" rid="EQ16">Equations 9</xref><xref ref-type="disp-formula" rid="EQ17"/>&#x2013;<xref ref-type="disp-formula" rid="EQ18">11</xref>.</p>
<disp-formula id="EQ16">
<label>(9)</label>
<mml:math id="M133">
<mml:msub>
<mml:mi mathvariant="script">B</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mfrac>
<mml:mi>A</mml:mi>
<mml:mi>&#x03BB;</mml:mi>
</mml:mfrac>
<mml:mfenced close="]" open="[">
<mml:mrow>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
<mml:mo>&#x2212;</mml:mo>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
</mml:mrow>
</mml:mfenced>
</mml:math>
</disp-formula>
<disp-formula id="EQ17">
<label>(10)</label>
<mml:math id="M134">
<mml:msub>
<mml:mi mathvariant="script">B</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mfrac>
<mml:mi>A</mml:mi>
<mml:mi>&#x03BB;</mml:mi>
</mml:mfrac>
<mml:mfenced close="]" open="[">
<mml:mrow>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
<mml:mo>&#x2212;</mml:mo>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
</mml:mrow>
</mml:mfenced>
</mml:math>
</disp-formula>
<disp-formula id="EQ18">
<label>(11)</label>
<mml:math id="M135">
<mml:msub>
<mml:mi mathvariant="script">B</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mfrac>
<mml:mi>A</mml:mi>
<mml:mi>&#x03BB;</mml:mi>
</mml:mfrac>
<mml:mfenced close="]" open="[">
<mml:mrow>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
<mml:mo>&#x2212;</mml:mo>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
</mml:mrow>
</mml:mfenced>
</mml:math>
</disp-formula>
<p>The total number of items purchased from the regular supplier is derived as <xref ref-type="disp-formula" rid="EQ19">Equation 12</xref>.</p>
<disp-formula id="E2">
<mml:math id="M136">
<mml:mi mathvariant="script">F</mml:mi>
<mml:mo>=</mml:mo>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mn>0</mml:mn>
</mml:mfenced>
<mml:mo>+</mml:mo>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mn>0</mml:mn>
</mml:mfenced>
<mml:mo>+</mml:mo>
<mml:msub>
<mml:mi mathvariant="script">B</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:math>
</disp-formula>
<disp-formula id="EQ19">
<label>(12)</label>
<mml:math id="M137">
<mml:mi mathvariant="script">F</mml:mi>
<mml:mo>=</mml:mo>
<mml:msub>
<mml:mi>W</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mo>+</mml:mo>
<mml:mi>D</mml:mi>
<mml:mfenced open="(" close=")">
<mml:mrow>
<mml:mn>1</mml:mn>
<mml:mo>+</mml:mo>
<mml:mi>L</mml:mi>
</mml:mrow>
</mml:mfenced>
<mml:mo>ln</mml:mo>
<mml:mfenced open="(" close=")">
<mml:mfrac>
<mml:mrow>
<mml:mn>1</mml:mn>
<mml:mo>+</mml:mo>
<mml:mi>L</mml:mi>
</mml:mrow>
<mml:mrow>
<mml:mn>1</mml:mn>
<mml:mo>+</mml:mo>
<mml:mi>L</mml:mi>
<mml:mo>&#x2212;</mml:mo>
<mml:msub>
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<mml:mn>2</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfrac>
</mml:mfenced>
<mml:mo>+</mml:mo>
<mml:mfrac>
<mml:mi>A</mml:mi>
<mml:mi>&#x03BB;</mml:mi>
</mml:mfrac>
<mml:mfenced close="]" open="[">
<mml:mrow>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
<mml:mo>&#x2212;</mml:mo>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
</mml:mrow>
</mml:mfenced>
</mml:math>
</disp-formula>
<p>The cost functions of the model are presented from <xref ref-type="disp-formula" rid="EQ20">Equations 13</xref><xref ref-type="disp-formula" rid="EQ21"/><xref ref-type="disp-formula" rid="EQ22"/><xref ref-type="disp-formula" rid="EQ23"/>&#x2013;<xref ref-type="disp-formula" rid="EQ24">18</xref>.</p>
<list list-type="simple">
<list-item>
<p>1)&#x00A0;&#x00A0;&#x00A0;Ordering Cost: Ordering costs are the charges a business incurs when placing an order with a supplier for goods, services, or raw materials. They are sometimes referred to as procurement costs or start-up costs. Here, we are considering three orders, such as ordinary, JIT 1 and JIT 2.</p>
</list-item>
</list>
<disp-formula id="EQ20">
<label>(13)</label>
<mml:math id="M138">
<mml:mi>O</mml:mi>
<mml:mi>C</mml:mi>
<mml:mo>=</mml:mo>
<mml:mi>I</mml:mi>
<mml:mo>+</mml:mo>
<mml:msub>
<mml:mi>J</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:mo>+</mml:mo>
<mml:msub>
<mml:mi>J</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:math>
</disp-formula>
<list list-type="simple">
<list-item>
<p>2)&#x00A0;&#x00A0;&#x00A0;Purchasing Cost: Purchasers must pay suppliers a certain sum called a purchasing cost when purchasing an inventory item. Here, we consider four purchasing costs, namely the purchase cost for a regular order, the purchase cost for expiry date constrained items, and the purchase cost for JIT 1 and JIT 2 items.</p>
</list-item>
</list>
<p>Purchasing cost is associated with the cost of</p>
<disp-formula id="EQ21">
<label>(14)</label>
<mml:math id="M139">
<mml:mi>P</mml:mi>
<mml:mi>C</mml:mi>
<mml:mo>=</mml:mo>
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>W</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mo>+</mml:mo>
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mrow>
<mml:msub>
<mml:mi>W</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mo>+</mml:mo>
<mml:msub>
<mml:mi mathvariant="script">B</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfenced>
<mml:mo>+</mml:mo>
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi mathvariant="script">B</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:mo>+</mml:mo>
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi mathvariant="script">B</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:math>
</disp-formula>
<list list-type="simple">
<list-item>
<p>3)&#x00A0;&#x00A0;&#x00A0;Holding Cost: Holding costs are the costs incurred to store inventory. Here, <inline-formula>
<mml:math id="M140">
<mml:msub>
<mml:mi>h</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
</mml:math>
</inline-formula> represents the holding cost per unit of time in <inline-formula>
<mml:math id="M141">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>. Moreover, <inline-formula>
<mml:math id="M142">
<mml:msub>
<mml:mi>h</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
</mml:math>
</inline-formula> represents the holding cost per unit of time in <inline-formula>
<mml:math id="M143">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
<mml:mtext>.</mml:mtext>
</mml:math>
</inline-formula></p>
</list-item>
</list>
<disp-formula id="E3">
<mml:math id="M144">
<mml:mi>H</mml:mi>
<mml:mi>C</mml:mi>
<mml:mo>=</mml:mo>
<mml:msub>
<mml:mi>h</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mfenced close="]" open="[">
<mml:mrow>
<mml:msubsup>
<mml:mstyle displaystyle="true">
<mml:mo stretchy="true">&#x222B;</mml:mo>
</mml:mstyle>
<mml:mn>0</mml:mn>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:msubsup>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mi>d</mml:mi>
<mml:mi>t</mml:mi>
</mml:mrow>
</mml:mfenced>
<mml:mo>+</mml:mo>
<mml:msub>
<mml:mi>h</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced close="]" open="[">
<mml:mrow>
<mml:msubsup>
<mml:mstyle displaystyle="true">
<mml:mo stretchy="true">&#x222B;</mml:mo>
</mml:mstyle>
<mml:mn>0</mml:mn>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
</mml:msubsup>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mi>d</mml:mi>
<mml:mi>t</mml:mi>
<mml:mo>+</mml:mo>
<mml:msubsup>
<mml:mstyle displaystyle="true">
<mml:mo stretchy="true">&#x222B;</mml:mo>
</mml:mstyle>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:msubsup>
<mml:msub>
<mml:mi>I</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mfenced open="(" close=")">
<mml:mi>t</mml:mi>
</mml:mfenced>
<mml:mi>d</mml:mi>
<mml:mi>t</mml:mi>
<mml:mo>+</mml:mo>
<mml:msubsup>
<mml:mstyle displaystyle="true">
<mml:mo stretchy="true">&#x222B;</mml:mo>
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<list list-type="simple">
<list-item>
<p>4)&#x00A0;&#x00A0;&#x00A0;Deterioration Cost: This cost is the amount of money lost due to inventory deterioration during storage.</p></list-item>
</list>
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<list list-type="simple">
<list-item>
<p>5)&#x00A0;&#x00A0;&#x00A0;Backlog Cost: The term &#x201C;backlog cost&#x201D; refers to the cost of running out of products. The loss of potential item sales profit, the damage to goodwill resulting from a permanent customer loss, and the resulting loss of future sales profit are all included in this cost. Therefore, the backlog cost is calculated as follows:</p></list-item>
</list>
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<list list-type="order">
<list-item>
<p>6)&#x00A0;&#x00A0;&#x00A0;Total cost of the system: The total cost of the system in a unit of time is the sum of all the associated costs.</p></list-item>
</list>
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<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
<mml:mfenced open="(" close=")">
<mml:mrow>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
<mml:mo>&#x2212;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfenced>
<mml:mo>&#x2212;</mml:mo>
<mml:msup>
<mml:mi>e</mml:mi>
<mml:mrow>
<mml:mi>&#x03BB;</mml:mi>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:mrow>
</mml:msup>
<mml:mfenced open="(" close=")">
<mml:mrow>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
<mml:mo>&#x2212;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfenced>
</mml:mtd>
</mml:mtr>
</mml:mtable>
</mml:mfenced>
</mml:mtd>
</mml:mtr>
</mml:mtable>
</mml:mfenced>
</mml:math>
</disp-formula>
<p>The classical analytic optimization method for two variables is used to optimize the system&#x2019;s total cost<inline-formula>
<mml:math id="M153">
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mtext>.</mml:mtext>
</mml:math>
</inline-formula> The following algorithm using MATLAB code is designed to achieve cost optimization:</p>
<list list-type="simple">
<list-item>
<p>Step 1: Initialize all the parameters.</p>
</list-item>
<list-item>
<p>Step 2: compute <inline-formula>
<mml:math id="M154">
<mml:mfrac>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfrac>
</mml:math>
</inline-formula> and <inline-formula>
<mml:math id="M155">
<mml:mfrac>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfrac>
</mml:math>
</inline-formula>. Apply the below necessary conditions to arrive at the critical points of the cost surface:</p>
</list-item>
</list>
<disp-formula id="E8">
<mml:math id="M156">
<mml:mfrac>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfrac>
<mml:mo>=</mml:mo>
<mml:mn>0</mml:mn>
<mml:mo>;</mml:mo>
<mml:mfrac>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfrac>
<mml:mo>=</mml:mo>
<mml:mn>0.</mml:mn>
</mml:math>
</disp-formula>
<list list-type="simple">
<list-item>
<p>Step 3: Find all second-order partial derivatives <inline-formula>
<mml:math id="M157">
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msup>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mn>2</mml:mn>
</mml:msup>
</mml:mrow>
</mml:mfrac>
</mml:math>
</inline-formula>, <inline-formula>
<mml:math id="M158">
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msup>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
<mml:mn>2</mml:mn>
</mml:msup>
</mml:mrow>
</mml:mfrac>
</mml:math>
</inline-formula>, <inline-formula>
<mml:math id="M159">
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfrac>
</mml:math>
</inline-formula>.</p>
</list-item>
<list-item>
<p>Step 4: Generate the Hessian matrix as follows:</p></list-item>
</list>
<disp-formula id="E9">
<mml:math id="M160">
<mml:mi>H</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
<mml:mo>=</mml:mo>
<mml:mfenced close="]" open="[">
<mml:mtable equalrows="true" equalcolumns="true">
<mml:mtr>
<mml:mtd>
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msup>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mn>2</mml:mn>
</mml:msup>
</mml:mrow>
</mml:mfrac>
</mml:mtd>
<mml:mtd>
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfrac>
</mml:mtd>
</mml:mtr>
<mml:mtr>
<mml:mtd>
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfrac>
</mml:mtd>
<mml:mtd>
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msup>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
<mml:mn>2</mml:mn>
</mml:msup>
</mml:mrow>
</mml:mfrac>
</mml:mtd>
</mml:mtr>
</mml:mtable>
</mml:mfenced>
</mml:math>
</disp-formula>
<list list-type="simple">
<list-item>
<p>Check for the critical points for which all second derivatives are as follows:</p>
</list-item>
<list-item>
<p>If, <inline-formula>
<mml:math id="M161">
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msup>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mn>2</mml:mn>
</mml:msup>
</mml:mrow>
</mml:mfrac>
<mml:mo>&#x003E;</mml:mo>
<mml:mn>0</mml:mn>
</mml:math>
</inline-formula>, <inline-formula>
<mml:math id="M162">
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msup>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
<mml:mn>2</mml:mn>
</mml:msup>
</mml:mrow>
</mml:mfrac>
<mml:mo>&#x003E;</mml:mo>
<mml:mn>0</mml:mn>
</mml:math>
</inline-formula> and<inline-formula>
<mml:math id="M163">
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfrac>
<mml:mo>&#x003E;</mml:mo>
<mml:mn>0</mml:mn>
</mml:math>
</inline-formula></p>
</list-item>
<list-item>
<p>Select the critical point that yields the discriminative value as follows:</p></list-item>
</list>
<disp-formula id="E10">
<mml:math id="M164">
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msup>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mn>2</mml:mn>
</mml:msup>
</mml:mrow>
</mml:mfrac>
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msup>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
<mml:mn>2</mml:mn>
</mml:msup>
</mml:mrow>
</mml:mfrac>
<mml:mo>&#x2212;</mml:mo>
<mml:mfrac>
<mml:mrow>
<mml:msup>
<mml:mo>&#x2202;</mml:mo>
<mml:mn>2</mml:mn>
</mml:msup>
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:mrow>
<mml:mrow>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mo>&#x2202;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mrow>
</mml:mfrac>
<mml:mo>&#x003E;</mml:mo>
<mml:mn>0</mml:mn>
</mml:math>
</disp-formula>
<list list-type="simple">
<list-item>
<p>Then, the Hessian matrix will be positive definite for such a point. Hence, the surface of the total cost function <inline-formula>
<mml:math id="M165">
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:math>
</inline-formula>is convex in nature.</p>
</list-item>
<list-item>
<p>Otherwise, go to step 3 and proceed with other critical points.</p>
</list-item>
<list-item>
<p>Step 5: Best optimum total cost is identified and denoted by <inline-formula>
<mml:math id="M166">
<mml:mi>T</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
<mml:mfenced open="(" close=")" separators=",">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
</mml:msub>
</mml:mfenced>
</mml:math>
</inline-formula>.</p>
</list-item>
<list-item>
<p>Step 6: Stop the procedure.</p>
</list-item>
</list>
<p>The time point <inline-formula>
<mml:math id="M167">
<mml:msubsup>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula> and<inline-formula>
<mml:math id="M168">
<mml:msubsup>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula>, which minimizes the total cost function, <inline-formula>
<mml:math id="M169">
<mml:mi>T</mml:mi>
<mml:mi>C</mml:mi>
</mml:math>
</inline-formula>say<inline-formula>
<mml:math id="M170">
<mml:mi>T</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>. It leads us to obtain the optimum total order quantity and backlog period.</p>
</sec>
<sec id="sec6">
<label>4</label>
<title>Numerical example and sensitivity analysis</title>
<sec id="sec7">
<label>4.1</label>
<title>Numerical example</title>
<p>The model is validated in the particular environment with the following parameter values:</p>
<p><inline-formula>
<mml:math id="M171">
<mml:msub>
<mml:mi>J</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>800</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M172">
<mml:msub>
<mml:mi>J</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>80</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M173">
<mml:msub>
<mml:mi>J</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>85</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M174">
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>58</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M175">
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>2</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>52</mml:mn>
<mml:mo>;</mml:mo>
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>62</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M176">
<mml:msub>
<mml:mi>P</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>64</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M177">
<mml:msub>
<mml:mi>d</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>3</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M178">
<mml:msub>
<mml:mi>d</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>5</mml:mn>
</mml:math>
</inline-formula>;<inline-formula>
<mml:math id="M179">
<mml:msub>
<mml:mi>W</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>100</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M180">
<mml:msub>
<mml:mi>h</mml:mi>
<mml:mi>R</mml:mi>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>7</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M181">
<mml:msub>
<mml:mi>h</mml:mi>
<mml:mi>O</mml:mi>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>6</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M182">
<mml:mi>A</mml:mi>
<mml:mo>=</mml:mo>
<mml:mn>3.8</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M183">
<mml:mi>D</mml:mi>
<mml:mo>=</mml:mo>
<mml:mn>7</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M184">
<mml:mi>&#x03B8;</mml:mi>
<mml:mo>=</mml:mo>
<mml:mn>0.23</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M185">
<mml:mi>&#x03BB;</mml:mi>
<mml:mo>=</mml:mo>
<mml:mn>0.29</mml:mn>
<mml:mo>;</mml:mo>
<mml:mi>L</mml:mi>
<mml:mo>=</mml:mo>
<mml:mn>7.7</mml:mn>
<mml:mo>;</mml:mo>
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>1</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>1.7</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M186">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>3</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>7</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M187">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>4</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>7.4</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M188">
<mml:msub>
<mml:mi>t</mml:mi>
<mml:mn>5</mml:mn>
</mml:msub>
<mml:mo>=</mml:mo>
<mml:mn>7.6</mml:mn>
</mml:math>
</inline-formula> in appropriate units.</p>
<p>We have arrived at the optimum outputs as follows:</p>
<p><inline-formula>
<mml:math id="M189">
<mml:msubsup>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
<mml:mo>=</mml:mo>
<mml:mn>4.06</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M190">
<mml:msubsup>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
<mml:mo>=</mml:mo>
<mml:mn>7.92</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M191">
<mml:mi>T</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
<mml:mo>=</mml:mo>
<mml:mn>2067.20</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M192">
<mml:msup>
<mml:mi mathvariant="script">F</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
<mml:mo>=</mml:mo>
<mml:mn>149.85</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M193">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>1</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
<mml:mo>=</mml:mo>
<mml:mn>12.27</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M194">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>2</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
<mml:mo>=</mml:mo>
<mml:mn>6.69</mml:mn>
</mml:math>
</inline-formula>;</p>
<p><inline-formula>
<mml:math id="M195">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>3</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
<mml:mo>=</mml:mo>
<mml:mn>11.17</mml:mn>
</mml:math>
</inline-formula>;<inline-formula>
<mml:math id="M196">
<mml:mi>P</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
<mml:mo>=</mml:mo>
<mml:mn>9581.00</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M197">
<mml:mi>H</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
<mml:mo>=</mml:mo>
<mml:mn>5056.90</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M198">
<mml:mi>D</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
<mml:mo>=</mml:mo>
<mml:mn>705.97</mml:mn>
</mml:math>
</inline-formula>; <inline-formula>
<mml:math id="M199">
<mml:mi>B</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
<mml:mo>=</mml:mo>
<mml:mn>42.97</mml:mn>
</mml:math>
</inline-formula></p>
<p>The total cost function for the above-said environment is presented in <xref ref-type="fig" rid="fig3">Figure 3</xref>.</p>
<fig position="float" id="fig3">
<label>Figure 3</label>
<caption>
<p>Total cost function.</p>
</caption>
<graphic xlink:href="fams-11-1410533-g003.tif"/>
</fig>
</sec>
<sec id="sec8">
<label>4.2</label>
<title>Sensitivity analysis</title>
<p>Any situation that involves decision-making may encounter a shift in parameter values due to uncertainty. The sensitivity analysis will play a significant role in decision-making when examining the effects of these adjustments. The sensitivity analysis of factors was performed using the same parameters considered in the same environment as in the numerical illustration. First, the demand parameter <inline-formula>
<mml:math id="M200">
<mml:mi>&#x03BB;</mml:mi>
</mml:math>
</inline-formula> is varied from 0.19 to 0.31. Furthermore, the demand parameter <inline-formula>
<mml:math id="M201">
<mml:mi>A</mml:mi>
</mml:math>
</inline-formula> is varied from 3.4 to 4.6. The corresponding optimum measures of the model are listed in <xref ref-type="table" rid="tab2">Table 1</xref>.</p>
<table-wrap position="float" id="tab2">
<label>Table 1</label>
<caption>
<p>Effect of variation of <inline-formula>
<mml:math id="M202">
<mml:mi>&#x03BB;</mml:mi>
</mml:math>
</inline-formula> and <inline-formula>
<mml:math id="M203">
<mml:mi>A</mml:mi>
</mml:math>
</inline-formula> on the optimizing measures.</p>
</caption>
<table frame="hsides" rules="groups">
<thead>
<tr>
<th/>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M204">
<mml:msubsup>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M205">
<mml:msubsup>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M206">
<mml:mi>T</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M207">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>1</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M208">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>2</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula>
</th>
</tr>
</thead>
<tbody>
<tr>
<td align="left" valign="top" colspan="6">
<inline-formula>
<mml:math id="M209">
<mml:mi>&#x03BB;</mml:mi>
</mml:math>
</inline-formula>
</td>
</tr>
<tr>
<td align="left" valign="top">0.19</td>
<td align="center" valign="top">3.21</td>
<td align="center" valign="top">9.94</td>
<td align="center" valign="top">1734.19</td>
<td align="center" valign="top">5.97</td>
<td align="center" valign="top">3.16</td>
</tr>
<tr>
<td align="left" valign="top">0.21</td>
<td align="center" valign="top">3.37</td>
<td align="center" valign="top">9.42</td>
<td align="center" valign="top">1804.91</td>
<td align="center" valign="top">6.90</td>
<td align="center" valign="top">3.67</td>
</tr>
<tr>
<td align="left" valign="top">0.23</td>
<td align="center" valign="top">3.50</td>
<td align="center" valign="top">8.97</td>
<td align="center" valign="top">1874.14</td>
<td align="center" valign="top">7.97</td>
<td align="center" valign="top">4.27</td>
</tr>
<tr>
<td align="left" valign="top">0.25</td>
<td align="center" valign="top">3.68</td>
<td align="center" valign="top">8.58</td>
<td align="center" valign="top">1941.32</td>
<td align="center" valign="top">9.2</td>
<td align="center" valign="top">4.96</td>
</tr>
<tr>
<td align="left" valign="top">0.27</td>
<td align="center" valign="top">3.86</td>
<td align="center" valign="top">8.23</td>
<td align="center" valign="top">2005.87</td>
<td align="center" valign="top">10.62</td>
<td align="center" valign="top">5.76</td>
</tr>
<tr>
<td align="left" valign="top">0.29</td>
<td align="center" valign="top">4.06</td>
<td align="center" valign="top">7.92</td>
<td align="center" valign="top">2067.20</td>
<td align="center" valign="top">12.27</td>
<td align="center" valign="top">6.69</td>
</tr>
<tr>
<td align="left" valign="top">0.31</td>
<td align="center" valign="top">4.26</td>
<td align="center" valign="top">7.64</td>
<td align="center" valign="top">2124.68</td>
<td align="center" valign="top">14.17</td>
<td align="center" valign="top">7.77</td>
</tr>
<tr>
<td align="left" valign="top" colspan="6"><italic>A</italic></td>
</tr>
<tr>
<td align="left" valign="top">3.4</td>
<td align="center" valign="top">3.75</td>
<td align="center" valign="top">8.10</td>
<td align="center" valign="top">1999.99</td>
<td align="center" valign="top">10.98</td>
<td align="center" valign="top">5.99</td>
</tr>
<tr>
<td align="left" valign="top">3.6</td>
<td align="center" valign="top">3.91</td>
<td align="center" valign="top">8.01</td>
<td align="center" valign="top">2034.78</td>
<td align="center" valign="top">11.63</td>
<td align="center" valign="top">6.34</td>
</tr>
<tr>
<td align="left" valign="top">3.8</td>
<td align="center" valign="top">4.06</td>
<td align="center" valign="top">7.92</td>
<td align="center" valign="top">2067.20</td>
<td align="center" valign="top">12.27</td>
<td align="center" valign="top">6.69</td>
</tr>
<tr>
<td align="left" valign="top">4</td>
<td align="center" valign="top">4.20</td>
<td align="center" valign="top">7.84</td>
<td align="center" valign="top">2097.48</td>
<td align="center" valign="top">12.92</td>
<td align="center" valign="top">7.04</td>
</tr>
<tr>
<td align="left" valign="top">4.2</td>
<td align="center" valign="top">4.32</td>
<td align="center" valign="top">7.76</td>
<td align="center" valign="top">2125.79</td>
<td align="center" valign="top">13.56</td>
<td align="center" valign="top">7.39</td>
</tr>
<tr>
<td align="left" valign="top">4.4</td>
<td align="center" valign="top">4.44</td>
<td align="center" valign="top">7.68</td>
<td align="center" valign="top">2152.29</td>
<td align="center" valign="top">14.21</td>
<td align="center" valign="top">7.75</td>
</tr>
<tr>
<td align="left" valign="top">4.6</td>
<td align="center" valign="top">4.55</td>
<td align="center" valign="top">7.61</td>
<td align="center" valign="top">2177.12</td>
<td align="center" valign="top">14.85</td>
<td align="center" valign="top">8.10</td>
</tr>
</tbody>
</table>
</table-wrap>
<p>Based on the values in <xref ref-type="table" rid="tab2">Table 1</xref>, we infer the following results: If the demand parameters<inline-formula>
<mml:math id="M210">
<mml:mi>&#x03BB;</mml:mi>
</mml:math>
</inline-formula>and <inline-formula>
<mml:math id="M211">
<mml:mi>A</mml:mi>
</mml:math>
</inline-formula> are increased, then the optimum <inline-formula>
<mml:math id="M212">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula>ordering quantities<inline-formula>
<mml:math id="M213">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>1</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula> and <inline-formula>
<mml:math id="M214">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>2</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula> are also increased by the impact of the decrease in the optimum total length of the cycle. As a result, the total optimal cost per unit of time also increases in an exponential trend. Such effect is depicted in <xref ref-type="fig" rid="fig4">Figures 4</xref>, <xref ref-type="fig" rid="fig5">5</xref>.</p>
<fig position="float" id="fig4">
<label>Figure 4</label>
<caption>
<p>Effect of variation in <inline-formula>
<mml:math id="M215">
<mml:mi>&#x03BB;</mml:mi>
</mml:math>
</inline-formula> on <inline-formula>
<mml:math id="M216">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>1</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula> and <inline-formula>
<mml:math id="M217">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>2</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula>.</p>
</caption>
<graphic xlink:href="fams-11-1410533-g004.tif"/>
</fig>
<fig position="float" id="fig5">
<label>Figure 5</label>
<caption>
<p>Effect of variation in <inline-formula>
<mml:math id="M218">
<mml:mi>A</mml:mi>
</mml:math>
</inline-formula> on <inline-formula>
<mml:math id="M219">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>1</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula> and <inline-formula>
<mml:math id="M220">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>2</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula>.</p>
</caption>
<graphic xlink:href="fams-11-1410533-g005.tif"/>
</fig>
<p>That is, the increase in both <inline-formula>
<mml:math id="M221">
<mml:mi>&#x03BB;</mml:mi>
</mml:math>
</inline-formula>and <inline-formula>
<mml:math id="M222">
<mml:mi>A</mml:mi>
</mml:math>
</inline-formula> values are negatively correlated with optimum total cycle length, which is true in nature, and positively correlated with optimum JIT purchasing quantities and optimum time interval in which the RW becomes empty. As a result, the optimum total cost is increased. Such an effect is depicted in <xref ref-type="table" rid="tab2">Table 1</xref>.</p>
<p>Additionally, the effect of variation of deterioration parameter <inline-formula>
<mml:math id="M223">
<mml:mi>&#x03B8;</mml:mi>
</mml:math>
</inline-formula> and expiry date <inline-formula>
<mml:math id="M224">
<mml:mi>L</mml:mi>
</mml:math>
</inline-formula> on the optimum measures is shown in <xref ref-type="table" rid="tab3">Table 2</xref>.</p>
<table-wrap position="float" id="tab3">
<label>Table 2</label>
<caption>
<p>Effect of variation of <inline-formula>
<mml:math id="M225">
<mml:mi>&#x03B8;</mml:mi>
</mml:math>
</inline-formula> and <inline-formula>
<mml:math id="M226">
<mml:mi>L</mml:mi>
</mml:math>
</inline-formula> on the optimizing measures.</p>
</caption>
<table frame="hsides" rules="groups">
<thead>
<tr>
<th/>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M227">
<mml:msubsup>
<mml:mi>t</mml:mi>
<mml:mn>2</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M228">
<mml:msubsup>
<mml:mi>t</mml:mi>
<mml:mn>6</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M229">
<mml:mi>T</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M230">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>3</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M231">
<mml:msup>
<mml:mi>N</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M232">
<mml:mi>P</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M233">
<mml:mi>H</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M234">
<mml:mi>D</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>
</th>
<th align="center" valign="top">
<inline-formula>
<mml:math id="M235">
<mml:mi>B</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>
</th>
</tr>
</thead>
<tbody>
<tr>
<td align="left" valign="top" colspan="10">
<inline-formula>
<mml:math id="M236">
<mml:mi>&#x03B8;</mml:mi>
</mml:math>
</inline-formula>
</td>
</tr>
<tr>
<td align="left" valign="top">0.19</td>
<td align="center" valign="top">3.50</td>
<td align="center" valign="top">7.87</td>
<td align="center" valign="top">2026.84</td>
<td align="center" valign="top">9.67</td>
<td align="center" valign="top">141.01</td>
<td align="center" valign="top">1159.1</td>
<td align="center" valign="top">660.7</td>
<td align="center" valign="top">79.5</td>
<td align="center" valign="top">4.98</td>
</tr>
<tr>
<td align="left" valign="top">0.21</td>
<td align="center" valign="top">3.80</td>
<td align="center" valign="top">7.90</td>
<td align="center" valign="top">2048.66</td>
<td align="center" valign="top">10.79</td>
<td align="center" valign="top">145.75</td>
<td align="center" valign="top">1185.9</td>
<td align="center" valign="top">650.5</td>
<td align="center" valign="top">84.9</td>
<td align="center" valign="top">5.3</td>
</tr>
<tr>
<td align="left" valign="top">0.23</td>
<td align="center" valign="top">4.06</td>
<td align="center" valign="top">7.92</td>
<td align="center" valign="top">2067.20</td>
<td align="center" valign="top">11.55</td>
<td align="center" valign="top">149.83</td>
<td align="center" valign="top">1209.6</td>
<td align="center" valign="top">640.5</td>
<td align="center" valign="top">89.7</td>
<td align="center" valign="top">5.6</td>
</tr>
<tr>
<td align="left" valign="top">0.25</td>
<td align="center" valign="top">4.28</td>
<td align="center" valign="top">7.94</td>
<td align="center" valign="top">2083.07</td>
<td align="center" valign="top">12.30</td>
<td align="center" valign="top">153.54</td>
<td align="center" valign="top">1230.9</td>
<td align="center" valign="top">630.8</td>
<td align="center" valign="top">94.0</td>
<td align="center" valign="top">5.8</td>
</tr>
<tr>
<td align="left" valign="top">0.27</td>
<td align="center" valign="top">4.47</td>
<td align="center" valign="top">7.95</td>
<td align="center" valign="top">2096.72</td>
<td align="center" valign="top">12.68</td>
<td align="center" valign="top">156.60</td>
<td align="center" valign="top">1249.3</td>
<td align="center" valign="top">622.0</td>
<td align="center" valign="top">98.0</td>
<td align="center" valign="top">5.9</td>
</tr>
<tr>
<td align="left" valign="top">0.29</td>
<td align="center" valign="top">4.63</td>
<td align="center" valign="top">7.96</td>
<td align="center" valign="top">2108.54</td>
<td align="center" valign="top">13.07</td>
<td align="center" valign="top">159.33</td>
<td align="center" valign="top">1257.2</td>
<td align="center" valign="top">613.8</td>
<td align="center" valign="top">101.8</td>
<td align="center" valign="top">6.1</td>
</tr>
<tr>
<td align="left" valign="top">0.31</td>
<td align="center" valign="top">4.78</td>
<td align="center" valign="top">7.97</td>
<td align="center" valign="top">2118.83</td>
<td align="center" valign="top">13.45</td>
<td align="center" valign="top">162.00</td>
<td align="center" valign="top">1281.4</td>
<td align="center" valign="top">605.1</td>
<td align="center" valign="top">104.9</td>
<td align="center" valign="top">6.2</td>
</tr>
<tr>
<td align="left" valign="top" colspan="10"><italic>L</italic></td>
</tr>
<tr>
<td align="left" valign="top">4.7</td>
<td align="center" valign="top">3.32</td>
<td align="center" valign="top">7.99</td>
<td align="center" valign="top">2128.8</td>
<td align="center" valign="top">14.22</td>
<td align="center" valign="top">149.06</td>
<td align="center" valign="top">1194.0</td>
<td align="center" valign="top">701.9</td>
<td align="center" valign="top">105.6</td>
<td align="center" valign="top">6.5</td>
</tr>
<tr>
<td align="left" valign="top">5.2</td>
<td align="center" valign="top">3.48</td>
<td align="center" valign="top">7.97</td>
<td align="center" valign="top">2115.1</td>
<td align="center" valign="top">13.45</td>
<td align="center" valign="top">149.21</td>
<td align="center" valign="top">1197.9</td>
<td align="center" valign="top">687.8</td>
<td align="center" valign="top">102.1</td>
<td align="center" valign="top">6.2</td>
</tr>
<tr>
<td align="left" valign="top">5.7</td>
<td align="center" valign="top">3.62</td>
<td align="center" valign="top">7.96</td>
<td align="center" valign="top">2103.1</td>
<td align="center" valign="top">13.07</td>
<td align="center" valign="top">149.52</td>
<td align="center" valign="top">1201.5</td>
<td align="center" valign="top">675.4</td>
<td align="center" valign="top">98.9</td>
<td align="center" valign="top">6.1</td>
</tr>
<tr>
<td align="left" valign="top">6.2</td>
<td align="center" valign="top">3.74</td>
<td align="center" valign="top">7.95</td>
<td align="center" valign="top">2092.5</td>
<td align="center" valign="top">12.68</td>
<td align="center" valign="top">149.62</td>
<td align="center" valign="top">1203.7</td>
<td align="center" valign="top">665.2</td>
<td align="center" valign="top">96.3</td>
<td align="center" valign="top">5.9</td>
</tr>
<tr>
<td align="left" valign="top">6.7</td>
<td align="center" valign="top">3.86</td>
<td align="center" valign="top">7.94</td>
<td align="center" valign="top">2083.1</td>
<td align="center" valign="top">12.30</td>
<td align="center" valign="top">149.80</td>
<td align="center" valign="top">1206.4</td>
<td align="center" valign="top">655.5</td>
<td align="center" valign="top">93.8</td>
<td align="center" valign="top">5.8</td>
</tr>
<tr>
<td align="left" valign="top">7.2</td>
<td align="center" valign="top">3.96</td>
<td align="center" valign="top">7.93</td>
<td align="center" valign="top">2074.7</td>
<td align="center" valign="top">11.92</td>
<td align="center" valign="top">149.78</td>
<td align="center" valign="top">1207.8</td>
<td align="center" valign="top">647.9</td>
<td align="center" valign="top">91.7</td>
<td align="center" valign="top">5.7</td>
</tr>
<tr>
<td align="left" valign="top">7.7</td>
<td align="center" valign="top">4.03</td>
<td align="center" valign="top">7.92</td>
<td align="center" valign="top">2067.2</td>
<td align="center" valign="top">11.55</td>
<td align="center" valign="top">149.83</td>
<td align="center" valign="top">1209.6</td>
<td align="center" valign="top">640.5</td>
<td align="center" valign="top">89.7</td>
<td align="center" valign="top">5.6</td>
</tr>
</tbody>
</table>
</table-wrap>
<p>The following managerial insights are obtained based on the computational findings.</p>
<p>It emphasizes the impact of the deterioration parameter <inline-formula>
<mml:math id="M237">
<mml:mi>&#x03B8;</mml:mi>
</mml:math>
</inline-formula> on purchase cost, holding cost, and deterioration cost. One may observe that the purchasing cost exhibits an increase, reflecting higher procurement expenses to compensate for the faster rate of deterioration. Holding cost demonstrates a decrease, indicating reduced storage costs due to decreased inventory levels caused by deterioration. Deterioration cost increases, corresponding to the amplified deterioration rate within the inventory system. It increases the optimum total cost of the system. It provides critical insights into the model&#x2019;s performance, showcasing its robustness and effectiveness in capturing real-world dynamics. The observed trends are shown in <xref ref-type="table" rid="tab3">Table 2</xref> and <xref ref-type="fig" rid="fig6">Figure 6</xref>, reinforcing the soundness and practical applicability of the inventory model in managing costs under varying deterioration rates.</p>
<fig position="float" id="fig6">
<label>Figure 6</label>
<caption>
<p>Effect of variation in deterioration parameter <inline-formula>
<mml:math id="M238">
<mml:mi>&#x03B8;</mml:mi>
</mml:math>
</inline-formula> on <inline-formula>
<mml:math id="M239">
<mml:mi>T</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
<mml:mo>,</mml:mo>
<mml:mi>P</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
<mml:mo>,</mml:mo>
<mml:mi>H</mml:mi>
<mml:mi>C</mml:mi>
<mml:msup>
<mml:mo>,</mml:mo>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>and <inline-formula>
<mml:math id="M240">
<mml:mi>D</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>.</p>
</caption>
<graphic xlink:href="fams-11-1410533-g006.tif"/>
</fig>
<p>Now, it is discussed the influence of prolonging the items&#x2019; expiry date <inline-formula>
<mml:math id="M241">
<mml:mi>L</mml:mi>
</mml:math>
</inline-formula> in inventory modeling for optimizing the total cost. As the expiry date <inline-formula>
<mml:math id="M242">
<mml:mi>L</mml:mi>
</mml:math>
</inline-formula> extends, purchasing cost increases, indicating short-expiry items are purchased for less price. Holding costs demonstrate a decrease, reflecting reduced storage expenses as inventory can be managed more efficiently over time, and deterioration costs experience a decrease, too. This results in a decrease in the total system&#x2019;s optimum cost. It confirms the model&#x2019;s robustness in adapting to variations in expiry dates while achieving cost optimization. The findings are substantiated by <xref ref-type="table" rid="tab3">Table 2</xref> and <xref ref-type="fig" rid="fig7">Figure 7</xref>, illustrating the model&#x2019;s capability to address practical scenarios effectively and affirming its sound performance in inventory management.</p>
<fig position="float" id="fig7">
<label>Figure 7</label>
<caption>
<p>Effect of varying expiry date <inline-formula>
<mml:math id="M243">
<mml:mi>L</mml:mi>
</mml:math>
</inline-formula> of items in the <inline-formula>
<mml:math id="M244">
<mml:mi>R</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula> on <inline-formula>
<mml:math id="M245">
<mml:mi>T</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
<mml:mo>,</mml:mo>
<mml:mi>P</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
<mml:mo>,</mml:mo>
<mml:mi>H</mml:mi>
<mml:mi>C</mml:mi>
<mml:msup>
<mml:mo>,</mml:mo>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>and <inline-formula>
<mml:math id="M246">
<mml:mi>D</mml:mi>
<mml:msup>
<mml:mi>C</mml:mi>
<mml:mo>&#x2217;</mml:mo>
</mml:msup>
</mml:math>
</inline-formula>.</p>
</caption>
<graphic xlink:href="fams-11-1410533-g007.tif"/>
</fig>
</sec>
</sec>
<sec id="sec9">
<label>5</label>
<title>Conclusion and future work</title>
<p>We have developed a two-warehouse deterministic inventory model with multiple purchases. The unconstrained expiry date items are stored in the<inline-formula>
<mml:math id="M247">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>. In addition, we incorporate finite<inline-formula>
<mml:math id="M248">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula>purchases for the partial backlog customers to avoid the lost sale. The model suggested the effect of reducing the lost sales by a finite number of <inline-formula>
<mml:math id="M249">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula> purchases in the stock-out interval. The model is validated in a specific environment by numerical examples, and it suggests that the retailer should opt for appropriate managerial decisions to optimize his total cost.</p>
<list list-type="bullet">
<list-item>
<p>The effect of changes in exponential demand parameters, deterioration rate, and extension of the constrained expiry date of the items on optimizing the cost functions are listed in tables and depicted in the figures, which are the recommendations and suggestions to the retailers to fix their optimum strategies and finalize their decisions to succeed in the highly competitive business environment.</p>
</list-item>
<list-item>
<p>If the demand parameters <inline-formula>
<mml:math id="M250">
<mml:mi>&#x03BB;</mml:mi>
</mml:math>
</inline-formula>and <inline-formula>
<mml:math id="M251">
<mml:mi>A</mml:mi>
</mml:math>
</inline-formula> are increased, then the optimum <inline-formula>
<mml:math id="M252">
<mml:mi>J</mml:mi>
<mml:mi>I</mml:mi>
<mml:mi>T</mml:mi>
</mml:math>
</inline-formula>ordering quantities<inline-formula>
<mml:math id="M253">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>1</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula> and <inline-formula>
<mml:math id="M254">
<mml:msubsup>
<mml:mi>B</mml:mi>
<mml:mn>2</mml:mn>
<mml:mo>&#x2217;</mml:mo>
</mml:msubsup>
</mml:math>
</inline-formula> are also increased by the impact on the decrease of the optimum total length of the cycle. As a result, the total optimal cost per unit of time also increases.</p>
</list-item>
<list-item>
<p>The holding cost and deterioration cost are moderately increased for the increase in the deterioration parameter <inline-formula>
<mml:math id="M255">
<mml:mi>&#x03B8;</mml:mi>
</mml:math>
</inline-formula>, whereas the purchase cost is highly decreased due to the increase of <inline-formula>
<mml:math id="M256">
<mml:mi>&#x03B8;</mml:mi>
</mml:math>
</inline-formula> in the <inline-formula>
<mml:math id="M257">
<mml:mi>O</mml:mi>
<mml:mi>W</mml:mi>
</mml:math>
</inline-formula>.</p>
</list-item>
</list>
<p>In the future, the present study may extend its scope to include factors such as price and advertisement-dependent demand, retailers&#x2019; late payment options with and without installment payments, screening of items, and system re-do facility. Incorporating these factors could yield fruitful suggestions and recommendations for many retailers in different business environments.</p>
</sec>
</body>
<back>
<sec sec-type="data-availability" id="sec10">
<title>Data availability statement</title>
<p>The original contributions presented in the study are included in the article/supplementary material. Further inquiries can be directed to the corresponding author.</p>
</sec>
<sec sec-type="author-contributions" id="sec11">
<title>Author contributions</title>
<p>RT: Conceptualization, Resources, Supervision, Writing &#x2013; original draft, Data curation, Formal analysis, Funding acquisition, Investigation, Methodology, Project administration, Software, Validation, Visualization, Writing &#x2013; review &#x0026; editing. JV: Conceptualization, Data curation, Formal analysis, Funding acquisition, Investigation, Methodology, Project administration, Resources, Software, Supervision, Validation, Visualization, Writing &#x2013; original draft, Writing &#x2013; review &#x0026; editing. MM: Conceptualization, Data curation, Formal analysis, Funding acquisition, Investigation, Methodology, Project administration, Resources, Software, Supervision, Validation, Visualization, Writing &#x2013; original draft, Writing &#x2013; review &#x0026; editing. JU: Conceptualization, Data curation, Formal analysis, Funding acquisition, Investigation, Methodology, Project administration, Resources, Software, Supervision, Validation, Visualization, Writing &#x2013; original draft, Writing &#x2013; review &#x0026; editing. SS: Conceptualization, Data curation, Formal analysis, Funding acquisition, Investigation, Methodology, Project administration, Resources, Software, Supervision, Validation, Visualization, Writing &#x2013; original draft, Writing &#x2013; review &#x0026; editing.</p>
</sec>
<sec sec-type="funding-information" id="sec12">
<title>Funding</title>
<p>The author(s) declare that financial support was received for the research, authorship, and/or publication of this article. This article was co-funded by the European Union under the REFRESH&#x2014;Research Excellence For Region Sustainability and High-tech Industries project number CZ.10.03.01/00/22_003/0000048 via the Operational Programme Just Transition.</p>
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<sec sec-type="COI-statement" id="sec13">
<title>Conflict of interest</title>
<p>The authors declare that the research was conducted in the absence of any commercial or financial relationships that could be construed as a potential conflict of interest.</p>
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<title>Publisher&#x2019;s note</title>
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